Тема: «Алгебра логики» Задание 1: Составьте таблицу истинности логического выражения:
и не и не и не или и . A
| B
| C
|
| A ∧
|
| А ∧ ∧
| A ∧
∧ ∧
| A ∧ C
| A ∧ ∧ ∧ ∨ A ∧ C
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 0
| 0
| 0
| 0
| 0
| 1
| 1
| 0
| 0
| 0
| 0
| 0
| 0
| 0
| 1
| 0
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| 1
| 0
| 0
| 0
| 0
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 0
| 1
| 1
| 0
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 1
| 1
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| 1
|
Задание 2. Составьте таблицы истинности для следующих логических формул
1. ;
X1
| X2
| X3
|
| X1 *
| X1+X2
|
| (X1+X2)*
| X1 * (X1+X2)*
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 1
| 1
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 1
| 0
| 0
| 1
|
2. ;
XX
| Y
| Z
| YZ
| X YZ
| (X YZ) ( YZ)
| 0
| 0
| 0
| 0
| 1
| 1
| 0
| 0
| 1
| 0
| 1
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| 0
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 1
|
3. ;
A
| B
| C
| AB
| B≡C
| A+(B≡C)
| AB A+(B≡C)
| 0
| 0
| 0
| 0
| 1
| 1
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 0
| 0
| 0
| 1
| 0
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 1
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 1
|
Задание 3: Какой логической функции соответствует таблица истинности?
A
| B
| C
| F
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 1
| 0
| 1
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 1
|
не или и ;
и или ;
не и или ;
не и и .
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