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Математические структуры данных. Задача на минимум Начальная симплекстаблица f 1 1 1
Т.к. Δ2 = -3 решение не оптимально
C
| 5
| 3
| 5
| 0
| 0
| 0
| 0
| 0
| 0
| 0
|
| Базис
| X1
| X2
| X3
| X4
| X5
| X6
| X7
| X8
| X9
| b
| Q
| X1
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| -
| X5
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 1
| -
| X6
| 0
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| X7
| 0
| 2
| 2
| 1
| 0
| 0
| 1
| 0
| 0
| 1
| ½
| X8
| 0
| -3
| -5
| 0
| 0
| 0
| 0
| 1
| 0
| 0
| -
| X3
| 0
| 1
| 6
| 2
| 0
| 0
| 0
| 0
| 1
| 2
| 2/6
| Δ
| 0
| -3
| -5
| 5
| 0
| 0
| 0
| 0
| 0
| 5
|
| В качестве базисной переменной x9 берём x3 и считаем дельты
C
| 5
| 3
| 5
| 0
| 0
| 0
| 0
| 0
| 0
| 0
|
| Базис
| X1
| X2
| X3
| X4
| X5
| X6
| X7
| X8
| X9
| b
| Q
| X1
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| -
| X5
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 1
| -
| X6
| 0
| -1/6
| 0
| -1/3
| 0
| 1
| 0
| 0
| -1/6
| 2/3
| 1
| X7
| 0
| 5/3
| 0
| 1/3
| 0
| 0
| 1
| 0
| -1/3
| 1/3
| ½
| X8
| 0
| -13/6
| 0
| 5/3
| 0
| 0
| 0
| 1
| 5/6
| 5/3
| -
| X3
| 0
| 1/6
| 1
| 1/3
| 0
| 0
| 0
| 0
| 1/6
| 1/3
| 1/3
| Δ
| 0
| -13/6
| 0
| 20/3
| 0
| 0
| 0
| 0
| 5/6
| 20/3
|
| Т.к. Δ2 = -13/6 решение не оптимально
C
| 5
| 3
| 5
| 0
| 0
| 0
| 0
| 0
| 0
| 0
|
| Базис
| X1
| X2
| X3
| X4
| X5
| X6
| X7
| X8
| X9
| b
| Q
| X1
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| -
| X5
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 0
| 1
| 1
| X6
| 0
| -1/6
| 0
| -1/3
| 0
| 1
| 0
| 0
| -1/6
| 2/3
| -
| X2
| 0
| 5/3
| 0
| 1/3
| 0
| 0
| 1
| 0
| -1/3
| 1/3
| 1/5
| X8
| 0
| -13/6
| 0
| 5/3
| 0
| 0
| 0
| 1
| 5/6
| 5/3
| -
| X3
| 0
| 1/6
| 1
| 1/3
| 0
| 0
| 0
| 0
| 1/6
| 1/3
| 2
| Δ
| 0
| -13/6
| 0
| 20/3
| 0
| 0
| 0
| 0
| 5/6
| 20/3
|
| |
|
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