лабы чм. Лабораторная работа 1 по теме Методы решения нелинейных уравнений
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Лабораторная работа 5. Методы решения |
№ вар | Уравнение | x0 | y0 | h0 | a | b |
1 | y' = x y2 | 0 | -2 | 0.4 | 0 | 4 |
2 | y' = y2 (x2+ x + 1) | 0 | -2 | 0.2 | 0 | 2 |
3 | y' = x3 y2 | 0 | -2 | 0.2 | 0 | 2 |
4 | y' = y / cos2(x) | 0 | 1 | 0.1 | 0 | 1 |
5 | y' = y cos(x) | 0 | 1 | 0.5 | 0 | 5 |
6 | y' = y2cos(x) | 0 | -1 | 0.4 | 0 | 4 |
7 | y' = x2 y + y | 0 | 1 | 0.2 | 0 | 2 |
8 | y' = (x – 1)2 y2 | 0 | -1 | 0.5 | 0 | 5 |
9 | y' = x3 y | 0 | 1 | 0.2 | 0 | 2 |
10 | y' = y2 sin(x) | 0 | 0.5 | 0.2 | 0 | 2 |
11 | y' = y sin(x) | 0 | 1 | 0.4 | 0 | 4 |
12 | y' = x y | 0 | 1 | 0.2 | 0 | 2 |
13 | y' = y2 / x | 1 | 1 | 0.2 | 1 | 2 |
14 | y' = x2 y | 0 | 1 | 0.2 | 0 | 2 |
15 | y' = y2 (2 – x) | 0 | -1 | 0.4 | 0 | 4 |
16 | y' = 3 x2 y2 | 0 | -4 | 0.2 | 0 | 2 |
17 | y' = y2 (ex + 4x) | 0 | -1 | 0.4 | 0 | 4 |
18 | y' = y (x – 1) | 0 | 1 | 0.4 | 0 | 4 |
19 | y' = x (1 + y2) | 0 | 0 | 0.2 | 0 | 1.6 |
20 | y' = x / (2y) | 0 | 1 | 0.4 | 0 | 4 |
21 | y' = y / (3 x2) | 1 | 1 | 0.2 | 1 | 3 |
22 | y' = 4 x e-3y | 1 | 0 | 0.2 | 1 | 3 |
23 | y' = 2 x y | 0 | 1 | 0.2 | 0 | 2 |
24 | y' = 2 x (y1/2) | 0 | 1 | 0.4 | 0 | 4 |
25 | y' = y2 ex | 0 | -2 | 0.4 | 0 | 4 |
26 | y' = x (1 – y2)1/2 | 0 | 0 | 0.4 | 0 | 1.6 |
27 | y' = (1 + x) y | 0 | 1 | 0.2 | 0 | 2 |
28 | y' = x2 (1 – y2)1/2 | 0 | 0 | 0.4 | 0 | 1.6 |
29 | y' = (x2 + x) y2 | 0 | -1 | 0.4 | 0 | 4 |
30 | y' = y2 / cos2(x) | 0 | -1 | 0.3 | 0 | 1.5 |