Задание 9. Заданы две логические функции и . Путем тождественных преобразований получите минимальную форму записи функций и проверьте, является ли функция тождественной функции .
; на наборах 0, 4
;
; на наборах 0, 1, 3, 7 ; на наборах 0, 4
-
x
| y
| z
| F2
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 1
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 0
|
-
x1
| x2
| x3
| 1
| 2
| 3
| 4
| 5
| 6
| 7
| 8
| F1
| 0
| 0
| 0
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 1
| 0
| 1
| 0
| 1
| 0
| 1
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 0
| 0
| 1
| 1
| 0
| 0
| 0
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 1
| 0
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 1
|
Логическая функция F1 не равна функции F2. ;
-
x1
| x2
| x3
| 1
| 2
| 3
| F1
| 0
| 0
| 0
| 1
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 0
| 1
| 1
| 0
| 1
| 0
| 1
| 0
| 1
| 1
| 0
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 0
| 0
| 0
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 1
| 0
| 1
| 1
| 1
| 1
| 0
| 1
| 1
| 1
|
-
x1
| x2
| x3
| 1
| 2
| 3
| 4
| F2
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 0
| 1
| 1
| 0
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 1
|
Логическая функция F1 не равна функции F2. ; на наборах 0, 1, 3, 7
-
x1
| x2
| x3
| 1
| 2
| 3
| 4
| 5
| 6
| 7
| F1
| 0
| 0
| 0
| 1
| 1
| 1
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 1
| 0
| 1
| 0
| 1
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 0
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 1
| 0
| 1
| 0
| 1
| 0
| 0
| 1
| 1
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 0
| 0
| 0
| 0
| 0
| 1
| 1
| 1
|
-
x
| y
| z
| F2
| 0
| 0
| 0
| 1
| 0
| 0
| 1
| 1
| 0
| 1
| 0
| 0
| 0
| 1
| 1
| 1
| 1
| 0
| 0
| 0
| 1
| 0
| 1
| 0
| 1
| 1
| 0
| 0
| 1
| 1
| 1
| 1
|
Логическая функция F1 не равна функции F2. |